#include<bits/stdc++.h> using namespace std; int main(){ long long n; cin>>n; if(n%3==2){ cout<<n/32+1; }else{ cout<<n/32; } return 0; }

#include<iostream> using namespace std; unsigned long long n; int main(){ cin>>n; if(n%3==2)cout<<n/32+1; else cout<<n/32; return 0; } 看完题解，加入团队吧

#include<iostream> using namespace std;int main(){long long n;cin >> n;if(n%3==2) cout<<n/32+1;else cout<<n/32;return 0;}

#include<bits/stdc++.h> using namespace std; int main(){ int n;定义变量n; cin>>n; if(n%3==2){ cout<<n/32+1<<endl;//公式; } else{ cout<<n/32<<endl; } }

#if 0 12345678910 1234567891011 123456789101112 0 1 1 #endif #include <bits/stdc++.h> using namespace std; int n; int main() { cin>>n; if(n%30) cout<<n/3*2; else if(n%31) cout<<n/32; else cout<<n/32+1; return 0; }

简单 #include<iostream> using namespace std; int main(){ long long n; cin >> n; if(n%3==2) cout<<n/32+1; else cout<<n/32; return 0; }