#include<iostream>
using namespace std;
unsigned long long n;
int main(){
    cin>>n;
    if(n%3==2)cout<<n/3*2+1;
    else cout<<n/3*2;
    return 0;
}
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除3问题

除3问题题解

#include<iostream>
using namespace std;
unsigned long long n;
int main(){
cin>>n;
if(n%3==2)cout<<n/32+1;
else cout<<n/3