CF1896B.AB Flipping

普及/提高-

通过率:0%

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题目描述

You are given a string ss of length nn consisting of characters A\texttt{A} and B\texttt{B} . You are allowed to do the following operation:

  • Choose an index 1in11 \le i \le n - 1 such that si=As_i = \texttt{A} and si+1=Bs_{i + 1} = \texttt{B} . Then, swap sis_i and si+1s_{i+1} .

You are only allowed to do the operation at most once for each index 1in11 \le i \le n - 1 . However, you can do it in any order you want. Find the maximum number of operations that you can carry out.

输入格式

Each test contains multiple test cases. The first line contains the number of test cases tt ( 1t10001 \le t \le 1000 ). Description of the test cases follows.

The first line of each test case contains a single integer nn ( 2n21052 \le n \le 2\cdot 10^5 ) — the length of string ss .

The second line of each test case contains the string ss ( si=As_i=\texttt{A} or si=Bs_i=\texttt{B} ).

It is guaranteed that the sum of nn over all test cases does not exceed 21052\cdot 10^5 .

输出格式

For each test case, print a single integer containing the maximum number of operations that you can carry out.

输入输出样例

  • 输入#1

    3
    2
    AB
    4
    BBBA
    4
    AABB

    输出#1

    1
    0
    3

说明/提示

In the first test case, we can do the operation exactly once for i=1i=1 as s1=As_1=\texttt{A} and s2=Bs_2=\texttt{B} .

In the second test case, it can be proven that it is not possible to do an operation.

In the third test case, we can do an operation on i=2i=2 to form ABAB\texttt{ABAB} , then another operation on i=3i=3 to form ABBA\texttt{ABBA} , and finally another operation on i=1i=1 to form BABA\texttt{BABA} . Note that even though at the end, s2=As_2 = \texttt{A} and s3=Bs_3 = \texttt{B} , we cannot do an operation on i=2i=2 again as we can only do the operation at most once for each index.

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