CF1905F.Field Should Not Be Empty

普及/提高-

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题目描述

You are given a permutation ^{\dagger} pp of length nn .

We call index xx good if for all y<xy < x it holds that py<pxp_y < p_x and for all y>xy > x it holds that py>pxp_y > p_x . We call f(p)f(p) the number of good indices in pp .

You can perform the following operation: pick 22 distinct indices ii and jj and swap elements pip_i and pjp_j .

Find the maximum value of f(p)f(p) after applying the aforementioned operation exactly once.

^{\dagger} A permutation of length nn is an array consisting of nn distinct integers from 11 to nn in arbitrary order. For example, [2,3,1,5,4][2,3,1,5,4] is a permutation, but [1,2,2][1,2,2] is not a permutation ( 22 appears twice in the array), and [1,3,4][1,3,4] is also not a permutation ( n=3n=3 but there is 44 in the array).

输入格式

Each test consists of multiple test cases. The first line of contains a single integer tt ( 1t21041 \le t \le 2 \cdot 10^4 ) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer nn ( 2n21052 \le n \le 2 \cdot 10^5 ) — the length of the permutation pp .

The second line of each test case contain nn distinct integers p1,p2,,pnp_1, p_2, \ldots, p_n ( 1pin1 \le p_i \le n ) — the elements of the permutation pp .

It is guaranteed that sum of nn over all test cases does not exceed 21052 \cdot 10^5 .

输出格式

For each test case, output a single integer — the maximum value of f(p)f(p) after performing the operation exactly once.

输入输出样例

  • 输入#1

    5
    5
    1 2 3 4 5
    5
    2 1 3 4 5
    7
    2 1 5 3 7 6 4
    6
    2 3 5 4 1 6
    7
    7 6 5 4 3 2 1

    输出#1

    3
    5
    2
    3
    2

说明/提示

In the first test case, p=[1,2,3,4,5]p = [1,2,3,4,5] and f(p)=5f(p)=5 which is already maximum possible. But must perform the operation anyway. We can get f(p)=3f(p)=3 by choosing i=1i=1 and j=2j=2 which makes p=[2,1,3,4,5]p = [2,1,3,4,5] .

In the second test case, we can transform pp into [1,2,3,4,5][1,2,3,4,5] by choosing i=1i=1 and j=2j=2 . Thus f(p)=5f(p)=5 .

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