CF1905F.Field Should Not Be Empty
普及/提高-
通过率:0%
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题目描述
You are given a permutation † p of length n .
We call index x good if for all y<x it holds that py<px and for all y>x it holds that py>px . We call f(p) the number of good indices in p .
You can perform the following operation: pick 2 distinct indices i and j and swap elements pi and pj .
Find the maximum value of f(p) after applying the aforementioned operation exactly once.
† A permutation of length n is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2,3,1,5,4] is a permutation, but [1,2,2] is not a permutation ( 2 appears twice in the array), and [1,3,4] is also not a permutation ( n=3 but there is 4 in the array).
输入格式
Each test consists of multiple test cases. The first line of contains a single integer t ( 1≤t≤2⋅104 ) — the number of test cases. The description of the test cases follows.
The first line of each test case contains a single integer n ( 2≤n≤2⋅105 ) — the length of the permutation p .
The second line of each test case contain n distinct integers p1,p2,…,pn ( 1≤pi≤n ) — the elements of the permutation p .
It is guaranteed that sum of n over all test cases does not exceed 2⋅105 .
输出格式
For each test case, output a single integer — the maximum value of f(p) after performing the operation exactly once.
输入输出样例
输入#1
5 5 1 2 3 4 5 5 2 1 3 4 5 7 2 1 5 3 7 6 4 6 2 3 5 4 1 6 7 7 6 5 4 3 2 1
输出#1
3 5 2 3 2
说明/提示
In the first test case, p=[1,2,3,4,5] and f(p)=5 which is already maximum possible. But must perform the operation anyway. We can get f(p)=3 by choosing i=1 and j=2 which makes p=[2,1,3,4,5] .
In the second test case, we can transform p into [1,2,3,4,5] by choosing i=1 and j=2 . Thus f(p)=5 .