CF1863C.MEX Repetition

You are given an array $a_1,a_2,\ldots, a_n$ of pairwise distinct integers from $0$ to $n$ . Consider the following operation:

• consecutively for each $i$ from $1$ to $n$ in this order, replace $a_i$ with $\operatorname{MEX}(a_1, a_2, \ldots, a_n)$ .

Here $\operatorname{MEX}$ of a collection of integers $c_1, c_2, \ldots, c_m$ is defined as the smallest non-negative integer $x$ which does not occur in the collection $c$ . For example, $\operatorname{MEX}(0, 2, 2, 1, 4) = 3$ and $\operatorname{MEX}(1, 2) = 0$ .

Print the array after applying $k$ such operations.

Each test contains multiple test cases. The first line contains the number of test cases $t$ ( $1 \le t \le 10^5$ ). The description of the test cases follows.

The first line of each test case contains two integers $n$ and $k$ ( $1\le n\le 10^5$ , $1\le k\le 10^9$ ).

The second line contains $n$ pairwise distinct integers $a_1,a_2,\ldots, a_n$ ( $0\le a_i\le n$ ) representing the elements of the array before applying the operations.

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$ .

For each test case, print all $n$ elements of the array after applying $k$ operations.

In the first test case, here is the entire process:

1. On the first operation, the array changes from $[1]$ to $[0]$ , since $\operatorname{MEX}(1) = 0$ .
2. On the second operation, the array changes from $[0]$ to $[1]$ , since $\operatorname{MEX}(0) = 1$ .

Thus, the array becomes $[1]$ after two operations.

In the second test case, the array changes as follows during one operation: $[{\mkern3mu\underline{\mkern-3mu {\bf 0}\mkern-3mu}\mkern3mu}, 1, 3] \rightarrow [2, {\mkern3mu\underline{\mkern-3mu {\bf 1}\mkern-3mu}\mkern3mu}, 3] \rightarrow [2, 0, {\mkern3mu\underline{\mkern-3mu {\bf 3}\mkern-3mu}\mkern3mu}] \rightarrow [2, 0, 1]$ .

In the third test case, the array changes as follows during one operation: $[{\mkern3mu\underline{\mkern-3mu {\bf 0}\mkern-3mu}\mkern3mu}, 2] \rightarrow [1, {\mkern3mu\underline{\mkern-3mu {\bf 2}\mkern-3mu}\mkern3mu}] \rightarrow [1, 0]$ . And during the second operation: $[{\mkern3mu\underline{\mkern-3mu {\bf 1}\mkern-3mu}\mkern3mu}, 0] \rightarrow [2, {\mkern3mu\underline{\mkern-3mu {\bf 0}\mkern-3mu}\mkern3mu}] \rightarrow [2, 1]$ .