CF1864B.Swap and Reverse
普及/提高-
通过率:0%
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题目描述
You are given a string s of length n consisting of lowercase English letters, and an integer k . In one step you can perform any one of the two operations below:
- Pick an index i ( 1≤i≤n−2 ) and swap si and si+2 .
- Pick an index i ( 1≤i≤n−k+1 ) and reverse the order of letters formed by the range [i,i+k−1] of the string. Formally, if the string currently is equal to s1…si−1sisi+1…si+k−2si+k−1si+k…sn−1sn , change it to s1…si−1si+k−1si+k−2…si+1sisi+k…sn−1sn .
You can make as many steps as you want (possibly, zero). Your task is to find the lexicographically smallest string you can obtain after some number of steps.
A string a is lexicographically smaller than a string b of the same length if and only if the following holds:
- in the first position where a and b differ, the string a has a letter that appears earlier in the alphabet than the corresponding letter in b .
输入格式
Each test contains multiple test cases. The first line contains the number of test cases t ( 1≤t≤104 ). The description of the test cases follows.
The first line of each test case contains two integers n and k ( 1≤k<n≤105 ).
The second line of each test case contains the string s of length n consisting of lowercase English letters.
It is guaranteed that the sum of n over all test cases does not exceed 105 .
输出格式
For each test case, print the lexicographically smallest string after doing some (possibly, zero) steps.
输入输出样例
输入#1
5 4 2 nima 5 3 panda 9 2 theforces 7 3 amirfar 6 4 rounds
输出#1
aimn aandp ceefhorst aafmirr dnorsu
说明/提示
In the first test case, we can obtain the string "aimn" using the following operations:
- Reverse the range [3,4] . The string turns into "niam".
- Swap s1 and s3 . The string turns into "ainm".
- Reverse the range [3,4] . The string turns into "aimn".
It can be proven that we cannot obtain any string lexicographically smaller than "aimn". Therefore, "aimn" is the answer.
In the second test case, we can obtain the string "aandp" using the following operations:
- Swap s3 and s5 . The string turns into "paadn".
- Swap s1 and s3 . The string turns into "aapdn".
- Swap s3 and s5 . The string turns into "aandp".
It can be proven that we cannot obtain any string lexicographically smaller than "aandp". Therefore, "aandp" is the answer.