CF1864D.Matrix Cascade

普及/提高-

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题目描述

There is a matrix of size n×nn \times n which consists of 0s and 1s. The rows are numbered from 11 to nn from top to bottom, the columns are numbered from 11 to nn from left to right. The cell at the intersection of the xx -th row and the yy -th column is denoted as (x,y)(x, y) .

AquaMoon wants to turn all elements of the matrix to 0s. In one step she can perform the following operation:

  • Select an arbitrary cell, let it be (i,j)(i, j) , then invert the element in (i,j)(i, j) and also invert all elements in cells (x,y)(x, y) for x>ix > i and xiyjx - i \ge \left|y - j\right| . To invert a value means to change it to the opposite: 0 changes to 1, 1 changes to 0.

Help AquaMoon determine the minimum number of steps she need to perform to turn all elements of the matrix to 0s. We can show that an answer always exists.

输入格式

Each test contains multiple test cases. The first line contains the number of test cases tt ( 1t1051 \le t \le 10^5 ). The description of the test cases follows.

The first line of each test case contains an integer nn ( 2n30002 \le n \le 3000 ).

The ii -th of the following nn lines contains a binary string only of characters 0 and 1, of length nn .

It is guaranteed that the sum of n2n^2 over all test cases does not exceed 90000009\,000\,000 .

输出格式

For each test case, print the minimum number of steps.

输入输出样例

  • 输入#1

    3
    5
    00100
    01110
    11111
    11111
    11111
    3
    100
    110
    110
    6
    010101
    111101
    011110
    000000
    111010
    001110

    输出#1

    1
    2
    15

说明/提示

In the first test case, we can use the following scheme:

  1. perform the operation on the cell (1,3)(1, 3) .

Clearly, the elements of the initial matrix are not all 0, so at least one operation is required. Thus, 11 is the answer.

In the second test case, we use the following scheme:

  1. perform the operation on the cell (3,3)(3, 3) ;
  2. perform the operation on the cell (1,1)(1, 1) .

It can be shown that there is no way to convert all elements to 0s in 00 or 11 steps, so the answer is exactly 22 .

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