CF1823B.Sort with Step
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题目描述
Let's define a permutation of length n as an array p of length n , which contains every number from 1 to n exactly once.
You are given a permutation p1,p2,…,pn and a number k . You need to sort this permutation in the ascending order. In order to do it, you can repeat the following operation any number of times (possibly, zero):
- pick two elements of the permutation pi and pj such that ∣i−j∣=k , and swap them.
Unfortunately, some permutations can't be sorted with some fixed numbers k . For example, it's impossible to sort [2,4,3,1] with k=2 .
That's why, before starting the sorting, you can make at most one preliminary exchange:
- choose any pair pi and pj and swap them.
Your task is to:
- check whether is it possible to sort the permutation without any preliminary exchanges,
- if it's not, check, whether is it possible to sort the permutation using exactly one preliminary exchange.
For example, if k=2 and permutation is [2,4,3,1] , then you can make a preliminary exchange of p1 and p4 , which will produce permutation [1,4,3,2] , which is possible to sort with given k .
输入格式
Each test contains multiple test cases. The first line contains the number of test cases t ( 1≤t≤104 ). The description of the test cases follows.
The first line of each test case contains two integers n and k ( 2≤n≤2⋅105 ; 1≤k≤n−1 ) — length of the permutation, and a distance between elements that can be swapped.
The second line of each test case contains n integers p1,p2,…,pn ( 1≤pi≤n ) — elements of the permutation p .
It is guaranteed that the sum of n over all test cases does not exceed 2⋅105 .
输出格式
For each test case print
- 0, if it is possible to sort the permutation without preliminary exchange;
- 1, if it is possible to sort the permutation with one preliminary exchange, but not possible without preliminary exchange;
- -1, if it is not possible to sort the permutation with at most one preliminary exchange.
输入输出样例
输入#1
6 4 1 3 1 2 4 4 2 3 4 1 2 4 2 3 1 4 2 10 3 4 5 9 1 8 6 10 2 3 7 10 3 4 6 9 1 8 5 10 2 3 7 10 3 4 6 9 1 8 5 10 3 2 7
输出#1
0 0 1 0 1 -1
说明/提示
In the first test case, there is no need in preliminary exchange, as it is possible to swap (p1,p2) and then (p2,p3) .
In the second test case, there is no need in preliminary exchange, as it is possible to swap (p1,p3) and then (p2,p4) .
In the third test case, you need to apply preliminary exchange to (p2,p3) . After that the permutation becomes [3,4,1,2] and can be sorted with k=2 .