CF1823D.Unique Palindromes
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题目描述
A palindrome is a string that reads the same backwards as forwards. For example, the string abcba is palindrome, while the string abca is not.
Let p(t) be the number of unique palindromic substrings of string t , i. e. the number of substrings t[l…r] that are palindromes themselves. Even if some substring occurs in t several times, it's counted exactly once. (The whole string t is also counted as a substring of t ).
For example, string t = abcbbcabcb has p(t)=6 unique palindromic substrings: a, b, c, bb, bcb and cbbc.
Now, let's define p(s,m)=p(t) where t=s[1…m] . In other words, p(s,m) is the number of palindromic substrings in the prefix of s of length m . For example, p( abcbbcabcb ,5) = p( abcbb )=5 .
You are given an integer n and k "conditions" ( k≤20 ). Let's say that string s , consisting of n lowercase Latin letters, is good if all k conditions are satisfied at the same time. A condition is a pair (xi,ci) and have the following meaning:
- p(s,xi)=ci , i. e. a prefix of s of length xi contains exactly ci unique palindromic substrings.
Find a good string s or report that such s doesn't exist.Look in Notes if you need further clarifications.
输入格式
Each test contains multiple test cases. The first line contains the number of test cases t ( 1≤t≤104 ). The description of the test cases follows.
The first line of each test case contains two integers n and k ( 3≤n≤2⋅105 ; 1≤k≤20 ) — length of good string s and number of conditions.
The second line of each test case contains k integers x1,x2,…,xk ( 3≤x1<x2<⋯<xk=n ) where xi is the length of the prefix in the i -th condition.
The third line of each test case contains k integers c1,c2,…,ck ( 3≤c1≤c2≤⋯≤ck≤min(109,2(n+1)n) ) where ci is the number of palindromic substrings in the i -th condition.
It is guaranteed that the sum of n over all test cases does not exceed 2⋅105 .
输出格式
For each test case, if there is no good string s of length n that satisfies all conditions, print NO.
Otherwise, print YES and a string s of length n , consisting of lowercase Latin letters, that satisfies all conditions. If there are multiple answers, print any of them.
输入输出样例
输入#1
7 10 2 5 10 5 6 3 1 3 3 4 2 3 4 3 3 4 2 3 4 3 4 4 1 4 5 10 3 4 6 10 4 5 8 10 4 4 6 7 10 4 5 7 8
输出#1
YES abcbbcabcb YES foo YES ayda YES wada NO YES abcbcacbab NO
说明/提示
In the first test case, string s = abcbbcabcb satisfies k=2 conditions:
- p(s,x1)=p(s,5)= p( abcbb )=5=s1 . Palindromic substrings are a, b, c, bb and bcb.
- p(s,x2)=p(s,10)= p( abcbbcabcb )=6=s2 . Palindromic substrings are the same as above, and one extra substring cbbc.
In the second test case, string foo satisfies k=1 condition:
- p( foo )=3 . Palindromic substrings are f, o and oo.
There are other possible answers.In the third test case, string ayda satisfies k=2 conditions:
- p( ayd )=3 . Palindromic substrings are a, y and d.
- p( ayda )=3 . Palindromic substrings are the same.
In the fourth test case, string wada satisfies k=2 conditions:
- p( wad )=3 . Palindromic substrings are w, a and d.
- p( wada )=4 . Palindromic substrings are the same, and one extra substring ada.
In the fifth test case, it can be proven that there is no string of length 4 which has 5 palindromic substrings.
In the sixth test case, string abcbcacbab satisfies k=3 conditions:
- p( abcb )=4 . Palindromic substrings are a, b, c and bcb.
- p( abcbca )=5 . Palindromic substrings are the same, and one extra substring cbc.
- p( abcbcacbab )=8 . Palindromic substrings are the same, and three extra substrings cac, bab and bcacb.