CF534B.Covered Path

普及/提高-

通过率:0%

AC君温馨提醒

该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。

题目描述

The on-board computer on Polycarp's car measured that the car speed at the beginning of some section of the path equals v1v_{1} meters per second, and in the end it is v2v_{2} meters per second. We know that this section of the route took exactly tt seconds to pass.

Assuming that at each of the seconds the speed is constant, and between seconds the speed can change at most by dd meters per second in absolute value (i.e., the difference in the speed of any two adjacent seconds does not exceed dd in absolute value), find the maximum possible length of the path section in meters.

输入格式

The first line contains two integers v1v_{1} and v2v_{2} ( 1<=v1,v2<=1001<=v_{1},v_{2}<=100 ) — the speeds in meters per second at the beginning of the segment and at the end of the segment, respectively.

The second line contains two integers tt ( 2<=t<=1002<=t<=100 ) — the time when the car moves along the segment in seconds, dd (0<=d<=10)(0<=d<=10) — the maximum value of the speed change between adjacent seconds.

It is guaranteed that there is a way to complete the segment so that:

  • the speed in the first second equals v1v_{1} ,
  • the speed in the last second equals v2v_{2} ,
  • the absolute value of difference of speeds between any two adjacent seconds doesn't exceed dd .

输出格式

Print the maximum possible length of the path segment in meters.

输入输出样例

  • 输入#1

    5 6
    4 2
    

    输出#1

    26
  • 输入#2

    10 10
    10 0
    

    输出#2

    100

说明/提示

In the first sample the sequence of speeds of Polycarpus' car can look as follows: 5, 7, 8, 6. Thus, the total path is 5+7+8+6=265+7+8+6=26 meters.

In the second sample, as d=0d=0 , the car covers the whole segment at constant speed v=10v=10 . In t=10t=10 seconds it covers the distance of 100 meters.

首页