CF351C.Jeff and Brackets

普及/提高-

通过率:0%

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题目描述

Jeff loves regular bracket sequences.

Today Jeff is going to take a piece of paper and write out the regular bracket sequence, consisting of nmnm brackets. Let's number all brackets of this sequence from 00 to nmnm - 11 from left to right. Jeff knows that he is going to spend ai mod na_{i\ mod\ n} liters of ink on the ii -th bracket of the sequence if he paints it opened and bi mod nb_{i\ mod\ n} liters if he paints it closed.

You've got sequences aa , bb and numbers nn , mm . What minimum amount of ink will Jeff need to paint a regular bracket sequence of length nmnm ?

Operation x mod yx\ mod\ y means taking the remainder after dividing number xx by number yy .

输入格式

The first line contains two integers nn and mm ( 1<=n<=20; 1<=m<=107;1<=n<=20; 1<=m<=10^{7}; mm is even). The next line contains nn integers: a0a_{0} , a1a_{1} , ...... , an1a_{n-1} (1<=ai<=10)(1<=a_{i}<=10) . The next line contains nn integers: b0b_{0} , b1b_{1} , ...... , bn1b_{n-1} (1<=bi<=10)(1<=b_{i}<=10) . The numbers are separated by spaces.

输出格式

In a single line print the answer to the problem — the minimum required amount of ink in liters.

输入输出样例

  • 输入#1

    2 6
    1 2
    2 1
    

    输出#1

    12
    
  • 输入#2

    1 10000000
    2
    3
    

    输出#2

    25000000
    

说明/提示

In the first test the optimal sequence is: ()()()()()()()()()()()() , the required number of ink liters is 1212 .

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