CF327C.Magic Five
普及/提高-
通过率:0%
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题目描述
There is a long plate s containing n digits. Iahub wants to delete some digits (possibly none, but he is not allowed to delete all the digits) to form his "magic number" on the plate, a number that is divisible by 5 . Note that, the resulting number may contain leading zeros.
Now Iahub wants to count the number of ways he can obtain magic number, modulo 1000000007 ( 109+7 ). Two ways are different, if the set of deleted positions in s differs.
Look at the input part of the statement, s is given in a special form.
输入格式
In the first line you're given a string a ( 1<=∣a∣<=105 ), containing digits only. In the second line you're given an integer k ( 1<=k<=109 ). The plate s is formed by concatenating k copies of a together. That is n=∣a∣⋅k .
输出格式
Print a single integer — the required number of ways modulo 1000000007 ( 109+7 ).
输入输出样例
输入#1
1256 1
输出#1
4
输入#2
13990 2
输出#2
528
输入#3
555 2
输出#3
63
说明/提示
In the first case, there are four possible ways to make a number that is divisible by 5: 5, 15, 25 and 125.
In the second case, remember to concatenate the copies of a . The actual plate is 1399013990.
In the third case, except deleting all digits, any choice will do. Therefore there are 26−1=63 possible ways to delete digits.