CF285C.Building Permutation
普及/提高-
通过率:0%
AC君温馨提醒
该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。
题目描述
Permutation p is an ordered set of integers p1,p2,...,pn , consisting of n distinct positive integers, each of them doesn't exceed n . We'll denote the i -th element of permutation p as pi . We'll call number n the size or the length of permutation p1,p2,...,pn .
You have a sequence of integers a1,a2,...,an . In one move, you are allowed to decrease or increase any number by one. Count the minimum number of moves, needed to build a permutation from this sequence.
输入格式
The first line contains integer n ( 1<=n<=3⋅105 ) — the size of the sought permutation. The second line contains n integers a1,a2,...,an ( −109<=ai<=109 ).
输出格式
Print a single number — the minimum number of moves.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
输入输出样例
输入#1
2 3 0
输出#1
2
输入#2
3 -1 -1 2
输出#2
6
说明/提示
In the first sample you should decrease the first number by one and then increase the second number by one. The resulting permutation is (2,1) .
In the second sample you need 6 moves to build permutation (1,3,2) .