CF204E.Little Elephant and Strings

普及/提高-

通过率:0%

AC君温馨提醒

该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。

题目描述

The Little Elephant loves strings very much.

He has an array aa from nn strings, consisting of lowercase English letters. Let's number the elements of the array from 1 to nn , then let's denote the element number ii as aia_{i} . For each string aia_{i} (1<=i<=n)(1<=i<=n) the Little Elephant wants to find the number of pairs of integers ll and rr (1<=l<=r<=ai)(1<=l<=r<=|a_{i}|) such that substring ai[l... r]a_{i}[l...\ r] is a substring to at least kk strings from array aa (including the ii -th string).

Help the Little Elephant solve this problem.

If you are not familiar with the basic notation in string problems, you can find the corresponding definitions in the notes.

输入格式

The first line contains two space-separated integers — nn and kk (1<=n,k<=105)(1<=n,k<=10^{5}) . Next nn lines contain array aa . The ii -th line contains a non-empty string aia_{i} , consisting of lowercase English letter. The total length of all strings aia_{i} does not exceed 10510^{5} .

输出格式

On a single line print nn space-separated integers — the ii -th number is the answer for string aia_{i} .

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

输入输出样例

  • 输入#1

    3 1
    abc
    a
    ab
    

    输出#1

    6 1 3 
    
  • 输入#2

    7 4
    rubik
    furik
    abab
    baba
    aaabbbababa
    abababababa
    zero
    

    输出#2

    1 0 9 9 21 30 0 
    

说明/提示

Let's assume that you are given string a=a1a2... aaa=a_{1}a_{2}...\ a_{|a|} , then let's denote the string's length as a|a| and the string's ii -th character as aia_{i} .

A substring a[l... r]a[l...\ r] (1<=l<=r<=a)(1<=l<=r<=|a|) of string aa is string alal+1... ara_{l}a_{l+1}...\ a_{r} .

String aa is a substring of string bb , if there exists such pair of integers ll and rr (1<=l<=r<=b)(1<=l<=r<=|b|) , that b[l... r]=ab[l...\ r]=a .

首页