CF216E.Martian Luck
普及/提高-
通过率:0%
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题目描述
You know that the Martians use a number system with base k . Digit b ( 0<=b<k ) is considered lucky, as the first contact between the Martians and the Earthlings occurred in year b (by Martian chronology).
A digital root d(x) of number x is a number that consists of a single digit, resulting after cascading summing of all digits of number x . Word "cascading" means that if the first summing gives us a number that consists of several digits, then we sum up all digits again, and again, until we get a one digit number.
For example, d(35047)=d((3+5+0+4)7)=d(157)=d((1+5)7)=d(67)=67 . In this sample the calculations are performed in the 7-base notation.
If a number's digital root equals b , the Martians also call this number lucky.
You have string s , which consists of n digits in the k -base notation system. Your task is to find, how many distinct substrings of the given string are lucky numbers. Leading zeroes are permitted in the numbers.
Note that substring s[i... j] of the string s=a1a2... an ( 1<=i<=j<=n ) is the string aiai+1... aj . Two substrings s[i1... j1] and s[i2... j2] of the string s are different if either i1=i2 or j1=j2 .
输入格式
The first line contains three integers k , b and n ( 2<=k<=109 , 0<=b<k , 1<=n<=105 ).
The second line contains string s as a sequence of n integers, representing digits in the k -base notation: the i -th integer equals ai ( 0<=a_{i}<k ) — the i -th digit of string s . The numbers in the lines are space-separated.
输出格式
Print a single integer — the number of substrings that are lucky numbers.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
输入输出样例
输入#1
10 5 6 3 2 0 5 6 1
输出#1
5
输入#2
7 6 4 3 5 0 4
输出#2
1
输入#3
257 0 3 0 0 256
输出#3
3
说明/提示
In the first sample the following substrings have the sought digital root: s[1... 2] = "3 2", s[1... 3] = "3 2 0", s[3... 4] = "0 5", s[4... 4] = "5" and s[2... 6] = "2 0 5 6 1".