CF83E.Two Subsequences
普及/提高-
通过率:0%
AC君温馨提醒
该题目为【codeforces】题库的题目,您提交的代码将被提交至codeforces进行远程评测,并由ACGO抓取测评结果后进行展示。由于远程测评的测评机由其他平台提供,我们无法保证该服务的稳定性,若提交后无反应,请等待一段时间后再进行重试。
题目描述
On an IT lesson Valera studied data compression. The teacher told about a new method, which we shall now describe to you.
Let a1,a2,...,an be the given sequence of lines needed to be compressed. Here and below we shall assume that all lines are of the same length and consist only of the digits 0 and 1 . Let's define the compression function:
- f( empty sequence )= empty string
- f(s)=s .
- f(s1,s2)= the smallest in length string, which has one of the prefixes equal to s1 and one of the suffixes equal to s2 . For example, f(001,011)=0011 , f(111,011)=111011 .
- f(a1,a2,...,an)=f(f(a1,a2,an−1),an) . For example, f(000,000,111)=f(f(000,000),111)=f(000,111)=000111 .
Valera faces a real challenge: he should divide the given sequence a1,a2,...,an into two subsequences b1,b2,...,bk and c1,c2,...,cm , m+k=n , so that the value of S=∣f(b1,b2,...,bk)∣+∣f(c1,c2,...,cm)∣ took the minimum possible value. Here ∣p∣ denotes the length of the string p .
Note that it is not allowed to change the relative order of lines in the subsequences. It is allowed to make one of the subsequences empty. Each string from the initial sequence should belong to exactly one subsequence. Elements of subsequences b and c don't have to be consecutive in the original sequence a , i. e. elements of b and c can alternate in a (see samples 2 and 3).
Help Valera to find the minimum possible value of S .
输入格式
The first line of input data contains an integer n — the number of strings ( 1<=n<=2⋅105 ). Then on n lines follow elements of the sequence — strings whose lengths are from 1 to 20 characters, consisting only of digits 0 and 1 . The i+1 -th input line contains the i -th element of the sequence. Elements of the sequence are separated only by a newline. It is guaranteed that all lines have the same length.
输出格式
Print a single number — the minimum possible value of S .
输入输出样例
输入#1
3 01 10 01
输出#1
4
输入#2
4 000 111 110 001
输出#2
8
输入#3
5 10101 01010 11111 01000 10010
输出#3
17
说明/提示
Detailed answers to the tests:
- The best option is to make one of the subsequences empty, and the second one equal to the whole given sequence. ∣f(01,10,01)∣=∣f(f(01,10),01)∣=∣f(010,01)∣=∣0101∣=4 .
- The best option is: b=000,001,c=111,110. S=∣f(000,001)∣+∣f(111,110)∣=∣0001∣+∣1110∣=8 .
- The best option is: b=10101,01010,01000,c=11111,10010. S=∣10101000∣+∣111110010∣=17 .