#include <iostream> using namespace std; int main() { int n; cin>>n; bool flag=true; for (int i=2;i<n;i++){ }

#include<iostream> using namespace std; int main(){ int n; cin >> n; bool flag=1; for(int i=2;i<=n-1;i++ ){ if( n%i0 ){ flag = 0; break; } } if( n1 ) flag = 0; if( flag == 1 )cout<<"Yes"; else cout<<"No"; return 0; }

#include<iostream> using namespace std; int main() { int n; cin >> n; }

#include <iostream> using namespace std; int main(){ int n,i; cin >> n; bool flag; if(n == 2){ flag = true; }else{ for(i = 2; i <= n - 1; i++){ if(n % i == 0){ flag = false; break; } } if(i == n){ flag = true; } } if(flag == true){ cout << "Yes"; }else{ cout << "No"; } return 0; }

n = int(input()) if n <= 1: print("No") else: is_prime = True for i in range(2, int(n ** 0.5) + 1): if n % i == 0: is_prime = False break if is_prime: print("Yes") else: print("No")

#include <iostream> using namespace std; int main(){ int n,i; cin >> n; bool flag; if(n == 2){ flag = true; }else{ for(i = 2; i <= n - 1; i++){ if(n % i == 0){ flag = false; break; } } if(i == n){ flag = true; } } if(flag == true){ cout << "Yes"; }else{ cout << "No"; } return 0; }

#输入一个数 n=int(input()) #判断你是否为质数 for i in range (2,n): if n%i==0: print("No") break else: if n !=1: print("Yes") else: print("no")

#include <iostream> #include <cmath> using namespace std; int main(){ int n; cin >> n; int a; if(n == 2){ cout << "Yes"; return 0; } if(n == 1){ cout << "No"; return 0; } if(n == 0){ cout << "No"; return 0; } for(int i = 2; i <= sqrt(n); i++){ if(n % i == 0){ a = 0; break; } else a = 1; } if(a) cout << "Yes"; else cout << "No"; return 0; }

只需要根骨头

劳资上答案 睁大眼睛看好了

#include<bits/stdc++.h> using namespace std; int main(){ int n; cin >> n; for(int i=2;i<n;i++){ if(n%i0){ cout << "No"; return 0; } } if(n1){ cout << "No"; return 0; } cout << "Yes"; return 0; }

666，这个好像挺复杂 #include<bits/stdc++.h> using namespace std; int zs(int n) { if (n < 2) { return 0; } int t = sqrt(n); for (int i = 2; i <= t; i++) { if (n % i == 0) { return 0; } } return 1; } int main() { int n; cin >> n; if (zs(n)) { cout << "Yes"; } else { cout << "No"; } return 0; }