//#include<iostream> #include<cstdio> //#include<algorithm> //#include<cmath> using namespace std; const double Pi=3.14159; int main() { double r; scanf("%lf",&r); printf("%.4lf %.4lf %.4lf",2r,2rPi,Pir*r); return 0; }

#include <bits/stdc++.h> using namespace std; int main(){ double a; cin>>a; printf("%.4f",a2); cout<<" "; printf("%.4f",a23.14159); cout<<" "; printf("%.4f",aa*3.14159); return 0; }

#include <iostream> #include <iomanip> using namespace std; int main() { double PI,r; cin>>r; PI=3.14159; cout<<fixed<<setprecision(4)<<r2; cout<<' '; cout<<fixed<<setprecision(4)<<r2PI; cout<<' '; cout<<fixed<<setprecision(4)<<rr*PI; return 0; }

#include<iostream> #include <iomanip> using namespace std; int main(){ double a,pi=3.14159; cin >> a; cout << fixed<<setprecision(4)<<2a << " " <<fixed<<setprecision(4)<< 2api << " " << fixed<<setprecision(4)<<aa*pi; return 0; }

#include<iostream> #include<cstdio> using namespace std; int main(){ double r, d = 0, c = 0, s = 0; double PI = 3.14159; cin >> r; d = r * 2; c = r * 2 *PI; s = r * r * PI; printf("%.4f", d); cout << " "; printf("%.4f", c); cout << " "; printf("%.4f", s); return 0; }

先分别吧直径、周长、面积算出来再用printf来保留小数 代码如下： 看了我题解后： 错误人数 正确人数 0 114514

#include <bits/stdc++.h> using namespace std; int main(){ double r; cin>>r; printf("%.4f %.4f %.4f",r2,r23.14159,rr*3.14159); return 0; }

#include<bits/stdc++.h> using namespace std; int main() { double r,pl = 3.14159; scanf("%lf",&r); printf("%.4lf",r * 2); cout << " "; printf("%.4lf",r * 2 * pl); cout << " "; printf("%.4lf",r * r * pl); return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ double r; ？？？？？("%？？",&r); double a=2.0*？; double b=2.0r3.14159; double c=rr3.14159; printf("%.？？ %.4f %.4f",a,b,c); return 0; }

#include<bits/stdc++.h> using namespace std; int main() { double r; cin>>r; cout<<setprecision(4)<<fixed<<r2.<<" "<<r23.14159<<" "<<rr*3.14159; }

反手一个命名空间

#include<iostream> #include<cstdio> using namespace std; int main(){ double r, d = 0, c = 0, s = 0; double PI = 3.14159; cin >> r; d = r * 2; c = r * 2 *PI; s = r * r * PI; printf("%.4f", d); cout << " "; printf("%.4f", c); cout << " "; printf("%.4f", s); return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ double r,pl = 3.14159; scanf("%lf",&r); printf("%.4lf",r * 2); cout << " "; printf("%.4lf",r * 2 * pl); cout << " "; printf("%.4lf",r * r * pl); return 0; }

非常简单好吧~