十分简单，挑战用最短代码： 高精度害死肝 就那么简单

我保证这是最短的代码

#include<iostream> using namespace std; int main(){ long long a,b; cin>>a>>b; long long final; final=a+b; cout<<final; }

#include<bits/stdc++.h> #define N 210 using namespace std; int as[N],bs[N],lena,lenb; string a,b; int main(){ cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++)as[i]=a[lena-i-1]-'0'; for(int i=0;i<lenb;i++)bs[i]=b[lenb-i-1]-'0'; int length=max(lena,lenb); for(int i=0;i<length;i++)as[i]+=bs[i]; for(int i=0;i<length;i++){ if(as[i]>9){ as[i+1]; as[i]-=10; if(i==length-1)length; } } while(length&&as[length]==0)length--; for(int i=length;i>=0;i--)cout<<as[i]; cout<<endl; }

#include<iostream> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<a+b; return 0; }

#include<iostream> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<a+b; }

#include <iostream> using namespace std; int main(){ long long a; long long b; cin >> a >> b; cout << a+b; return 0; }

#include <iostream> using namespace std; int main(){ int a , b; cin >> a >> b; cout << a + b; return 0; }

by QFIT

a+b zhijie,cin,shuchuxiangjia

#include<iostream> #include<cstdio> using namespace std; int main(){ int a,b; scanf("%d%d",&a,&b); printf("%d\n",a+b); return 0; }

#include<bits/stdc++.h> using namespace std; int main(){ int a,b; cin>>a>>b; cout <<a+b;//114514 }

cout<<5; return 0;

#include<iostream> using namespace std; int main(){ long long a,b; cin>>a>>b; cout<<a+b; return 0; }

#include <iostream> using namespace std; int main() {long long a, b; cin >> a >> b; cout << a + b; return 0;}