题解

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
int main()
{
    ll n,sum=0;
    cin >> n;
    while (n > 0)
    {
        n /= 2;
        sum++;
    }
    sum--;
    cout << sum << endl;
    for (int i=0;i<sum;i++)
    {
        cout << (ll)pow(2,i) << endl;
    }
    return 0;
}