题解

#include<bits/stdc++.h>
using namespace std;

int main()
{
	int t;
	cin >> t;
	while(t--)
	{
		int a,b,c,d,k;
		cin>>a>>b>>c>>d>>k;
		long long z= (long long)abs(a-c) + (long long)abs(b-d);
		if(k>=z && (k-z)%2==0) //如果k够了,并且多出来的部分是2的倍数
			cout << "Yes\n";
		else
			cout << "No\n";			
	}
	return 0;
}