还是贪心

如果有i个糖果，那么快乐值总和s0假设为in2，要小于等于真正的快乐值总和s，翻译过来就是贪心

# include <iostream>
using namespace std;
int main()
{
    long long n, s;
    int i=0;
    cin >> n >> s;
    while (i <= n + 1)
    {
        if (i * (n * 2) <= s) i++;
        else
        {
            cout << i - 1 << endl;
            return 0;
        }
    }
    cout << i - 1 << endl;
    return 0;
}