题解
2023-03-17 22:19:28
发布于:上海
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#include <stdio.h>
int main()
{
int i,n,x[10005],y[10005],a[10005],b[10005],x1,y1,k=1;
scanf("%d",&n);
for(i=0;i<n;i++)
scanf("%d%d%d%d",&x[i],&y[i],&a[i],&b[i]);
scanf("%d%d",&x1,&y1);
for(i=n-1;i>=0;i--)
{
if((x1>=x[i]&&x1<=x[i]+a[i])&&(y1>=y[i]&&y1<=y[i]+b[i]))
{ printf("%d\n",i+1); k*=0;}
else continue;
if((x1>=x[i]&&x1<=x[i]+a[i])&&(y1>=y[i]&&y1<=y[i]+b[i]))
break;
}
if(k==1) printf("-1\n");
return 0;
}
这里空空如也
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