题解

#include<iostream>
using namespace std;
int n,mi,zhiyi;
char b[1005][1005],a[1005][1005];
int main(){
	cin>>n;
	for(int i=1;i<=n;i++){
		for(int j=1;j<=n;j++){
			cin>>a[i][j];
		}
	}
	for(int i=1;i<=n;i++){
		for(int j=1;j<=n;j++){
			cin>>b[i][j];
			if(b[i][j]=='+'){
				if(a[i][j]==a[j][i])mi++;
			}
			else if(b[i][j]=='-'){
				if(a[i][j]!=a[j][i])zhiyi++;
			}
			else zhiyi++;
		}
	}
	cout<<mi+zhiyi<<" "<<mi;
}