题解

#include<iostream>
using namespace std;
int n,mi,zhiyi;
char b[1005][1005],a[1005][1005];
int main(){
cin>>n;
for(int i=1;i<=n;i++){
for(int j=1;j<=n;j++){
cin>>a[i][j];
}
}
for(int i=1;i<=n;i++){
for(int j=1;j<=n;j++){
cin>>b[i][j];
if(b[i][j]=='+'){
if(a[i][j]a[j][i])mi++;
}
else if(b[i][j]'-'){
if(a[i][j]!=a[j][i])zhiyi++;
}
else zhiyi++;
}
}
cout<<mi+zhiyi<<" "<<mi;
}