嘿嘿!题解来咯!

#include<iostream>
using namespace std;
int main(){
int n;
cin>>n;
if(n == 9)cout<<"除夕";
if(n == 10)cout<<"初一";
if(n == 11)cout<<"初二";
if(n == 12)cout<<"初三";
if(n == 13)cout<<"初四";
if(n == 14)cout<<"初五";
if(n == 15)cout<<"初六";
if(n == 16)cout<<"初七";
return 0;
}
上面是第一种方法，用了八个单分支
下面是用switch的方法:
#include<iostream>
using namespace std;
int main(){
int n;
cin>>n;
switch(n){
case 9:cout<<"除夕";break;
case 10:cout<<"初一";break;
case 11:cout<<"初二";break;
case 12:cout<<"初三";break;
case 13:cout<<"初四";break;
case 14:cout<<"初五";break;
case 15:cout<<"初六";break;
case 16:cout<<"初七";break;
}
return 0;
}
嘿！学废了吗?