全部评论 2

  • #include<bits/stdc++.h>
    using namespace std;
    const int N = 100001;
    int n;
    double sum1 = 0, sum2 = 0;
    struct stu {
    	double t;
    	int id;
    } a[N];
    bool cmp(stu aa, stu bb) {
    	return aa.t < bb.t;
    }
    int main() {
    	cin >> n;
    	for (int i = 1; i <= n; ++i) {
    		cin >> a[i].t;
    		a[i].id = i;
    	}
    	sort(a + 1, a + 1 + n, cmp);
    	for (int i = 1; i <= n; ++i)
    		cout << a[i].id << " ";
    	cout << endl;
    	for (int i = 1; i < n; i++) {
    		sum1 = sum1 + a[i].t;
    		sum2 = sum2 + sum1;
    	}
    	cout << fixed << setprecision(2) << sum2 * 1.0 / n;
    	return 0;
    }
    

    2024-07-26 来自 浙江

    0
  • sdfgnm

    2024-07-16 来自 广东

    0
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