解法可以冷门，但不能邪门（

#include <iostream>
#include <cstdio>
using namespace std;
string a = "0001";
void _init(){
	a = a + a + a + a + a;
	a = a + a + a + a + a;
	a[99] = '0';
	a += a;
	a += a;
	a[399] = '1';
	for(int i = 1; i <= 10; i++) a += a;
}
int main(){
	_init();
	int n;
	cin >> n; 
	if(a[n - 1] == '1') cout << "YES";
	else cout << "NO"; 

	return 0;
}