2行题解

#include<bits/stdc++.h>
int a,b,c,n,d;int a_(int a1,int b1,int c1,int n1){d=1000;a=n1/d/d;b=n1/d%d;c=n1%d;return abc;}using namespace std;int main(){cin>>n;cout<<a_(0,0,0,n);}