题解

#include<bits/stdc++.h>
#define int long long
using namespace std;
double a,b,c,d,cnt;
double f(double x)
{
return (apow(x,3))+(bpow(x,2))+(c*x)+d;
}
signed main()
{
cin>>a>>b>>c>>d;
for(double i=-100;i<=100;i+=0.001)
{
if(cnt>=3)
{
break;
}
if(f(i)*f(i+0.001)<0)
{
printf("%.2f ",i);
cnt++;
}
}
return 0;
}