题解：这题会了吗（不懂看看准没事）

鸡兔同笼

共两种方法

Do you understand the problem of the chicken and the rabbit in the cage?

#include<iostream>
using namespace std;
long long a, b, i, j=0;
int main(){

cin >> a >> b;
i = a;
__方法一：模拟__
while(true){
    if (i*2+j*4 == b){
        cout << i << endl << j << endl;
        break;
    }
    i--;
    j++;
}
__方法二：公式__
//int n = (b-a*2)/2;
//cout << a-n << endl << n;
return 0;

}