题解

来一发贪心，能闪就闪。

#include <iostream>
using namespace std;
int main(){
	int t1,t2,temp,s1,s2=0,s3=0;
    cin >> t1 >> s1 >> t2;
    temp=t2;
    while (s1>s2 && t2>0){
        s2+=17;
        if (t1>=10){
			s3+=60,t1-=10;
		}else{
        	t1+=4;
		}
        s2=max(s2,s3);
        --t2;
    }
    if (s2<s1){
    	cout<<"No\n"<<s2<<endl;
	}else{
    	cout<<"Yes\n"<<temp-t2<<endl;
	}
    return 0;
}