简单的高精度

#include<bits/stdc++.h>
using namespace std;
int a1[1005],b1[1005],ans[1005];
int main(){
    string a,b;
    cin >> a >> b;
    reverse(a.begin(),a.end());
    reverse(b.begin(),b.end());
    int c1 = max(a.size(),b.size());
    for(int i = 0;i < a.size();i ++){
        a1[i] = a[i] - '0';
    }
    for(int i = 0;i < b.size();i ++){
        b1[i] = b[i] - '0';
    }
    for(int i = 0;i < c1;i ++){
        int tmp;
        tmp = a1[i] + b1[i] + ans[i];
        ans[i] = tmp % 10;
        ans[i + 1] += tmp / 10;
    }
    if(ans[c1] == 1){
        c1 ++;
    }
    for(int i = c1 - 1;i >= 0;i --){
        cout << ans[i];
    }
    return 0;
}