你们有没有实力啊?
2023-09-24 10:03:21
发布于:四川
#include<iostream>
#include<string>
#include<cstring>
#include<cstdio>
using namespace std;
const int N = 1005;
struct bign{
int len,s[N];
bign() { memset(s,0,sizeof(s)); len=1; }
bign(int num) { *this=num; }
bign(char *num) { *this=num; }
bign operator =(int num){
char c[N];
sprintf(c,"%d",num);
*this=c;
return *this;
}
bign operator =(const char *num)
{
len=strlen(num);
for (int i=0;i<len;i++) s[i]=num[len-1-i]-'0';
return *this;
}
string str(){
string res="";
for (int i=0;i<len;i++) res=(char)(s[i]+'0')+res;
return res;
}
void clean()
{
while (len>1&&!s[len-1]) len--;
}
bign operator +(const bign &b){
bign c;
c.len=0;
for (int i=0,g=0;g||i<len||i<b.len;i++)
{
int x=g;
if (i<len) x+=s[i];
if (i<b.len) x+=b.s[i];
c.s[c.len++]=x%10;
g=x/10;
}
return c;
}
bign operator -(const bign &b)
{
bign c;
c.len=0;
int x;
for (int i=0,g=0;i<len;i++)
{
x=s[i]-g;
if (i<b.len) x-=b.s[i];
if (x>=0) g=0;
else{
x+=10;
g=1;
};
c.s[c.len++]=x;
}
c.clean();
return c;
}
bign operator *(const bign &b)
{
bign c;
c.len=len+b.len;
for (int i=0;i<len;i++) for (int j=0;j<b.len;j++) c.s[i+j]+=s[i]*b.s[j];
for (int i=0;i<c.len-1;i++) { c.s[i+1]+=c.s[i]/10; c.s[i]%=10; }
c.clean();
return c;
}
bool operator <(const bign &b)
{
if (len!=b.len) return len<b.len;
for (int i=len-1;i>=0;i--)
if (s[i]!=b.s[i]) return s[i]<b.s[i];
return false;
}
bign operator +=(const bign &b)
{
*this=*this+b;
return *this;
}
bign operator -=(const bign &b)
{
*this=*this-b;
return *this;
}
};
istream& operator >>(istream &in,bign &x)
{
string s;
in>>s;
x=s.c_str();
return in;
}
ostream& operator <<(ostream &out,bign &x)
{
out<<x.str();
return out;
}
int main(){
bign a,b,c;
ios::sync_with_stdio(false);
cin>>a>>b;
c=a+b;
cout<<c<<endl;
return 0;
}
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