不需要while和if,else的解法

#include<bits/stdc++.h>
using namespace std;

int main()
{
    int n,x;
    cin >> n;
    int ar1[n],ar2[n+1];
    for (int i=0;i<n;i++)
        cin >> ar1[i];
    cin >> x;
    for (int i=0;i<n;i++)
		ar2[i]=ar1[i];
    ar2[n]=x;
    sort(ar2,ar2+n+1);
    for (int i=0;i<=n;i++)
        cout << ar2[i] << ' ';
}