题解 (新方法: switch
2023-08-02 11:36:14
发布于:广东
46阅读
2回复
3点赞
#include<bits/stdc++.h>
using namespace std;
int main(){
int n,m;
cin>>n>>m;
switch(m){
case 1:case 3:case 5: case 7:case 8:case 10:case 12:{
cout<<31<<endl;
break;
}
case 4:case 6:case 9: case 11:{
cout<<30<<endl;
break;
}
case 2:{
if(n%4==0&&n%100!=0||n%400==0){
cout<<29<<endl;
}
else{
cout<<28<<endl;
}
break;
}
}
return 0;
}
全部评论 2
int year, month,day; cin >> year >>month; switch (month){ case 1:day = 31; break; case 2:day = 28; break; case 3:day = 31; break; case 4:day = 30; break; case 5:day = 31; break; case 6:day = 30; break; case 7:day = 31; break; case 8:day = 31; break; case 9:day = 30; break; case 10:day = 31; break; case 11:day = 30; break; default: day = 31; } day = (year%4==0&&year%100!=0)||year%400==0?day+=1:day+=0; cout << day;
这个易懂
2025-06-12 来自 广东
0看到这个题解我才想起来以前学习的switch(● ̄(エ) ̄●)我怎么这么聪明啊
2024-08-27 来自 浙江
0
有帮助,赞一个