题解

#include<bits/stdc++.h>
using namespace std;

int main()
{
    int n;
    cin >> n;
    int a[n][n];
    for (int i=0;i<n;i++)
    {
        for (int j=0;j<n;j++)
        {
            if (i%2==0) a[i][j]=i*n+j+1;
            else a[i][n-j-1]=i*n+j+1;
        }
    }
    for (int i=0;i<n*n;i++)
        cout << a[i/n][i%n] << (i%n==n-1 ? '\n':' ');
    return 0;
}