题解

#include <iostream>
using namespace std;
int n, maxx=0, minx=105, t, sum;
int main()
{
    cin >> n;
    for (int i=1; i<=n; i++)
    {
        int maxf = 0, minf = 105;
        for (int j=1; j<=3; j++)
        {
            cin >> t;
            sum += t;
            maxf = max(maxf, t);
            minf = min(minf, t);
        }
        sum -= maxf + minf;
        minx = min(minx, maxf);
        maxx = max(maxx, minf);
    }
    printf("%d %d %.1lf\n", minx, maxx, sum*1.0/n);
    return 0; 
}