这道题非常的简单

#include<iostream>
using namespace std;

int is_leap(int x){
if(x%40&&x%100!=0||x%4000) return true;
else return 0;
}
int main() {
int n;
cin >> n;
if(is_leap(n)) cout << "Y" << endl;
else cout << "N" << endl;

return 0;
}