辗转相除法求gcd

#include <iostream>
using namespace std;
int gcd(int a,int b){
    if(!b) return a;
    return gcd(b,a%b);
}
int main(){
    int a,b;
    cin>>a>>b;
    int g=gcd(a,b);
    a/=g;
    b/=g;
    cout<<a<<' '<<b;
    return 0;
}