实际上是无权图，样例错了

#include <iostream>
using namespace std;
int a[105][105];
int n, m, q, x, y, z;
int main(){
	cin >> n >> m >> q;
	for(int i = 1; i <= m; i++){
		cin >> x >> y;
		a[x][y] = 1;
	}while(q--){
		cin >> x >> y;
		if(!a[x][y]) cout << "Accepted\n";
		else cout << "Cancel\n";
	}
	return 0;
}