题解

由于n ≤ 500，因此这题可以用暴力枚举。
代码如下：

#include<bits/stdc++.h>
using namespace std;

int a[505];

int main(){
	int n;
    cin >> n;
    for(int i = 0;i < n;i ++) cin >> a[i];
    int minn = 1e9,maxn = -10000;
    for(int i = 0;i < n;i ++){
    	for(int j = 0;j < n;j ++){
        	int x = a[i],y = a[j];
            maxn = max(maxn,abs(x) - y);
            minn = min(minn,abs(x) - y);
        }
    }
    cout << maxn << " " << minn;
	return 0;
}