题解

贪心，也没说吃几个，那就全吃了（
吃掉一盘菜就把所需的对应元素逐个减少，如果最后都小于 $0$ 就说明已经足够了.

#include <iostream>
#include <cstdio>
#define int long long
using namespace std;
int a[100005];
signed main(){
	cin.tie(nullptr) -> sync_with_stdio(0);
	cout.tie(nullptr) -> sync_with_stdio(0);
	int n, m;
	cin >> m >> n;
	for(int i = 1; i <= n; i++) cin >> a[i];
	int x;
	for(int i = 1; i <= m; i++){
		for(int j = 1; j <= n; j++) cin >> x, a[j] -= x;//减去营养
	}
	for(int i = 1; i <= n; i++){
		if(a[i] > 0){
			cout << "No";//还有元素没摄取完毕
			return 0;
		}
	}
	cout << "Yes";

	return 0;
}