题解

#include<iostream>
#include<string>
using namespace std;
int main(){
char c;
int n;
cin>>n>>c;
if(n<=1000){
n=8;
}else if(n>=1000){
if(n%500!=0){
n=n/500500+500;
n=(n-1000)/5004+8;
}else{
n=(n-1000)/500*4+8;
}
}
if(c=='y'){
n+=5;
}
cout<<n;
return 0;
}