题解

那字符一定是2的倍数啊，单身狗怎么能平均分配呢（

#include <iostream>
#include <cstdio>
using namespace std;
int bucket[1005];
int main(){
    string s1, s2;
    cin >> s1 >> s2;
    int i;
    for(i = 0; s1[i] != '\0'; i++){
        if(s2[i] == '\0'){//多余的操作1
            cout << "No";
            return 0;
        }
        bucket[s1[i]]++, bucket[s2[i]]++;//记录
    }
    if(s2[i] != '\0'){//多余的操作2
        cout << "No";
        return 0;
    }
    for(int i = 1; i <= 1000; i++){
        if(bucket[i] & 1){
            cout << "No";
        	return 0;
        }
    }
    cout << "Yes";

	return 0;
}