简单

#include <iostream>
using namespace std;
int main(){
int n,k,v;
long long m;
cin>>n>>m>>k>>v;
long long sum=0;
if(n%k==0){
sum=n*(v7/10);
}
else{
sum=n/kk*(v7/10)+n%kv;
}
if(sum<=m){
cout<<"YES"<<endl;
cout<<m-sum;
}
else{
cout<<"NO"<<endl;
cout<<sum-m;
}
return 0;
}