题解

太坑了！！！！！！

题解

#include<iostream>
using namespace std;

int main()
{
    long long n,m,k,u,x=0,y=0;
    cin >> n >> m >> k >> u;
    y=n/k*k;
    x=y*(u*7/10)+u*(n-y);
    if(x>m)
    {
        cout << "NO" << endl << x-m;
    }
    else
    {
        cout << "YES" << endl << m-x;
    }
    return 0;
}