抽象题解

看得懂的都重开了

#include <iostream>
#include <cstdio>
using namespace std;
int a[105][105];
bool check(int x){
	bool ct = 0;
	while(x){
		ct ^= x % 2;
		x /= 10;
	}return ct;
}
int main(){
	int n, m, ct = 0;
	cin >> n >> m;
	for(int i = 1; i <= n; i++){
		for(int j = 1; j <= m; j++){
			cin >> a[i][j];
			ct += check(a[i][j]);
		}
	}cout << ct;

	return 0;
}

时间复杂度：$O(nmlog_{10}a_i)$