题解

#include <bits/stdc++.h>
using namespace std;
long long n,a,b;
int main(){
	int t;
	cin>>t;
	while(t--){
		cin>>n>>a>>b;
		if(2*a<=b) cout<<n*a<<endl;
		else{
			if(n%2==0) cout<<(n/2)*b<<endl;
			else cout<<n/2*b+a<<endl;
		}
	}
    return 0;
}