题解 if（YYDS）

#include<bits/stdc++.h>
#include<fstream>
#include<cmath>
using namespace std;
int main(){
freopen("beautiful.in","r",stdin);
freopen("beautiful.out","w",stdout);
int a;
cin >>a;
int b[105][105];
for(int i=1;i<=a;i++){
for(int j=1;j<=2;j++){
for(int k=1;k<=2;k++){
cin >>b[j][k];
}
}
if(b[1][1]<b[1][2]&&b[1][1]<b[2][1]&&b[2][1]<b[2][2]&&b[1][2]<b[2][2]){
cout <<"YES"<<endl;
}else if(b[1][1]>b[2][1]&&b[1][1]<b[1][2]&&b[2][1]<b[2][2]&&b[1][2]>b[2][2]) {
cout <<"YES"<<endl;
}else if(b[1][2]<b[1][1]&&b[1][1]>b[2][1]&&b[2][1]>b[2][2]&&b[1][2]>b[2][2]){
cout <<"YES"<<endl;
}else if(b[1][1]>b[1][2]&&b[1][1]<b[2][1]&&b[2][1]>b[2][2]&&b[2][2]>b[1][2]){
cout <<"YES"<<endl;
}else {
cout <<"NO"<<endl;
}
}

fclose(stdin);
fclose(stdout);
return 0;
}